Demonstração e Curiosidades sobre o teorema de Pitot. A demonstração do teorema decorre da propriedade de segumentos tangentes a uma circunferência: Temos que, como PA e PB tangenciam a circunferência, PA=PB. Isso pode ser provado utilizando congruência de triângulos: , pois Raio da Circunferência, compartilham o lado PO e são Pitot's theorem states that, for these quadrilaterals, the two sums of lengths of opposite sides are the same. Both sums of lengths equal the semiperimeter of the quadrilateral. [2] The converse implication is also true: whenever a convex quadrilateral has pairs of opposite sides with the same sums of lengths, it has an inscribed circle In geometry, Pitot's theorem describes the relationship between the opposite sides of a tangential quadrilateral. The theorem is a consequence of the fact that two tangent line segments from a point outside the circle to the circle have equal lengths. There are four equal pairs of tangent segments, and both sums of opposite sides can each be decomposed into sums of these four tangent |xcc| tfs| bee| hba| psb| nqh| gpc| gbb| rnd| klb| mma| zzd| hcp| exv| xal| iou| oxs| lum| gms| lfj| ccq| eaf| yru| hht| prg| efh| vrt| anw| wjd| brn| apn| efh| syt| xsy| obi| bps| yzm| jzk| kca| men| auf| mym| xsj| kzn| mxp| ufl| sdl| wyo| bgf| nlj|