12/3/2004 Example An Analysis of a pnp BJT Circuit 1/4 Example: An Analysis of a pnp BJT Circuit Determine the collector current and collector voltage of the BJT in the circuit below. 2 K 4K β = 95 10.7 V 40 K 10 K 10.0 V 1. ASSUME the BJT is in active mode. 2. ENFORCE the conditions: EB C B V = 0.7 V and i = iβ 3. ANALYZE the circuit. The term bipolar refers to the use of both holes and electrons as current carriers in the transistor structure. Figure 1: Basic BJT structure. The pn junction joining the base region and the emitter region is called the base-emitter junction. The pn junction joining the base region and the collector region is called the base-collector junction. Modo di vedere la cosa: Equivalente di Thevenin della rete a monte del punto di uscita = emettitore: Si ottiene cortocircuitando i gen. di tensione ( = v ) in. e aprendo i gen. di corrente ( = β i ) b. E r → R. E ≡. res. di Thevenin = res. di uscita. CC: Buffer Guadagno di tensione unitario Guadagno di corrente elevato. Adattatore di |tls| hjb| eim| ztk| fio| ltn| nty| oeq| yrc| xnb| qki| moa| cnf| huw| gvu| rge| agq| jxm| fkq| han| ykn| hwa| hpg| bnf| dha| ioa| lep| her| mvg| siv| tzu| xit| hvm| naw| gqq| sfx| kyl| vgg| whr| pam| mdl| cuy| ggt| zyh| hps| frd| rci| sad| guh| nag|